(x^2)-(2x)+10=0

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Solution for (x^2)-(2x)+10=0 equation:


Simplifying
(x2) + -1(2x) + 10 = 0
x2 + -1(2x) + 10 = 0

Remove parenthesis around (2x)
x2 + -1 * 2x + 10 = 0

Multiply -1 * 2
x2 + -2x + 10 = 0

Reorder the terms:
10 + -2x + x2 = 0

Solving
10 + -2x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -2x + -10 + x2 = 0 + -10

Reorder the terms:
10 + -10 + -2x + x2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -2x + x2 = 0 + -10
-2x + x2 = 0 + -10

Combine like terms: 0 + -10 = -10
-2x + x2 = -10

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -10 + 1

Reorder the terms:
1 + -2x + x2 = -10 + 1

Combine like terms: -10 + 1 = -9
1 + -2x + x2 = -9

Factor a perfect square on the left side:
(x + -1)(x + -1) = -9

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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